Here comes the answer to question 11 I posted yesterday. The correct answer is C.
This is a question about intermolecular forces as I discussed earlier in one of my blogs regarding the prediction of physical properties.
When the pressure of the gas is increased and the gas is about to condense, the gas can no longer deemed as ideal gas. At this point, the intermolecular forces between the gas molecules are no longer negligible. The stronger the intermolecular forces are, the less pressure is needed for the gas to condense.
All gases A, B, and C are non polar covalent bonded molecules. The only intermolecular force is London dispersion force. London dispersion force is caused by the instantaneous dipoles as molecules move around. The more complex the electronic structure of the molecule, the stronger the London dispersion force. Normally in a series of compound with similar structures, the higher the molar mass, the stronger the London dispersion force. As a result, answer C is the right answer.
Following is Question 12 of the series.
(A) A decrease in the strength of intermolecular attractions among molecules in the flask
(B) An increase in the strength of intermolecular attractions among molecules in the flask
(C) An increase in the number of molecules, which increases the frequency of collisions with the walls of the container
(D) An increase in the speed of the molecules that then collide with the walls of the container with greater force
I will post the answer and explanation tomorrow.
Thank you very much for reading my post, I am available to discuss any topics in AP chemistry. Please give me a call at 604-808-6827 or email me at vancouverchemistrytutor@gmail.com. My website is located at www.vancouverchemistrytutor.com.
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